(3x)^2/3+(4x)^1/3-4=0

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Solution for (3x)^2/3+(4x)^1/3-4=0 equation: 


x in (-oo:+oo)

((3*x)^2)/3+((4*x)^1)/3-4 = 0

((3*x)^2)/3+(4*x)/3-4 = 0

3*x^2+4/3*x-4 = 0

DELTA = (4/3)^2-(-4*3*4)

DELTA = 448/9

DELTA > 0

x = ((448/9)^(1/2)-4/3)/(2*3) or x = (-(448/9)^(1/2)-4/3)/(2*3)

x = ((448/9)^(1/2)-4/3)/6 or x = (-((448/9)^(1/2)+4/3))/6

x in { (-((448/9)^(1/2)+4/3))/6, ((448/9)^(1/2)-4/3)/6 }

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